Optimal. Leaf size=172 \[ -\frac{\sec ^{10}(c+d x)}{10 a d}+\frac{\sec ^8(c+d x)}{8 a d}-\frac{7 \tanh ^{-1}(\sin (c+d x))}{256 a d}+\frac{\tan (c+d x) \sec ^9(c+d x)}{10 a d}-\frac{\tan (c+d x) \sec ^7(c+d x)}{80 a d}-\frac{7 \tan (c+d x) \sec ^5(c+d x)}{480 a d}-\frac{7 \tan (c+d x) \sec ^3(c+d x)}{384 a d}-\frac{7 \tan (c+d x) \sec (c+d x)}{256 a d} \]
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Rubi [A] time = 0.219143, antiderivative size = 172, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 6, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.207, Rules used = {2835, 2611, 3768, 3770, 2606, 14} \[ -\frac{\sec ^{10}(c+d x)}{10 a d}+\frac{\sec ^8(c+d x)}{8 a d}-\frac{7 \tanh ^{-1}(\sin (c+d x))}{256 a d}+\frac{\tan (c+d x) \sec ^9(c+d x)}{10 a d}-\frac{\tan (c+d x) \sec ^7(c+d x)}{80 a d}-\frac{7 \tan (c+d x) \sec ^5(c+d x)}{480 a d}-\frac{7 \tan (c+d x) \sec ^3(c+d x)}{384 a d}-\frac{7 \tan (c+d x) \sec (c+d x)}{256 a d} \]
Antiderivative was successfully verified.
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Rule 2835
Rule 2611
Rule 3768
Rule 3770
Rule 2606
Rule 14
Rubi steps
\begin{align*} \int \frac{\sec ^7(c+d x) \tan ^2(c+d x)}{a+a \sin (c+d x)} \, dx &=\frac{\int \sec ^9(c+d x) \tan ^2(c+d x) \, dx}{a}-\frac{\int \sec ^8(c+d x) \tan ^3(c+d x) \, dx}{a}\\ &=\frac{\sec ^9(c+d x) \tan (c+d x)}{10 a d}-\frac{\int \sec ^9(c+d x) \, dx}{10 a}-\frac{\operatorname{Subst}\left (\int x^7 \left (-1+x^2\right ) \, dx,x,\sec (c+d x)\right )}{a d}\\ &=-\frac{\sec ^7(c+d x) \tan (c+d x)}{80 a d}+\frac{\sec ^9(c+d x) \tan (c+d x)}{10 a d}-\frac{7 \int \sec ^7(c+d x) \, dx}{80 a}-\frac{\operatorname{Subst}\left (\int \left (-x^7+x^9\right ) \, dx,x,\sec (c+d x)\right )}{a d}\\ &=\frac{\sec ^8(c+d x)}{8 a d}-\frac{\sec ^{10}(c+d x)}{10 a d}-\frac{7 \sec ^5(c+d x) \tan (c+d x)}{480 a d}-\frac{\sec ^7(c+d x) \tan (c+d x)}{80 a d}+\frac{\sec ^9(c+d x) \tan (c+d x)}{10 a d}-\frac{7 \int \sec ^5(c+d x) \, dx}{96 a}\\ &=\frac{\sec ^8(c+d x)}{8 a d}-\frac{\sec ^{10}(c+d x)}{10 a d}-\frac{7 \sec ^3(c+d x) \tan (c+d x)}{384 a d}-\frac{7 \sec ^5(c+d x) \tan (c+d x)}{480 a d}-\frac{\sec ^7(c+d x) \tan (c+d x)}{80 a d}+\frac{\sec ^9(c+d x) \tan (c+d x)}{10 a d}-\frac{7 \int \sec ^3(c+d x) \, dx}{128 a}\\ &=\frac{\sec ^8(c+d x)}{8 a d}-\frac{\sec ^{10}(c+d x)}{10 a d}-\frac{7 \sec (c+d x) \tan (c+d x)}{256 a d}-\frac{7 \sec ^3(c+d x) \tan (c+d x)}{384 a d}-\frac{7 \sec ^5(c+d x) \tan (c+d x)}{480 a d}-\frac{\sec ^7(c+d x) \tan (c+d x)}{80 a d}+\frac{\sec ^9(c+d x) \tan (c+d x)}{10 a d}-\frac{7 \int \sec (c+d x) \, dx}{256 a}\\ &=-\frac{7 \tanh ^{-1}(\sin (c+d x))}{256 a d}+\frac{\sec ^8(c+d x)}{8 a d}-\frac{\sec ^{10}(c+d x)}{10 a d}-\frac{7 \sec (c+d x) \tan (c+d x)}{256 a d}-\frac{7 \sec ^3(c+d x) \tan (c+d x)}{384 a d}-\frac{7 \sec ^5(c+d x) \tan (c+d x)}{480 a d}-\frac{\sec ^7(c+d x) \tan (c+d x)}{80 a d}+\frac{\sec ^9(c+d x) \tan (c+d x)}{10 a d}\\ \end{align*}
Mathematica [A] time = 2.59189, size = 122, normalized size = 0.71 \[ -\frac{210 \tanh ^{-1}(\sin (c+d x))-\frac{2 \left (105 \sin ^8(c+d x)+105 \sin ^7(c+d x)-385 \sin ^6(c+d x)-385 \sin ^5(c+d x)+511 \sin ^4(c+d x)+511 \sin ^3(c+d x)-279 \sin ^2(c+d x)+201 \sin (c+d x)+96\right )}{(\sin (c+d x)-1)^4 (\sin (c+d x)+1)^5}}{7680 a d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.079, size = 198, normalized size = 1.2 \begin{align*}{\frac{1}{256\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{4}}}-{\frac{1}{192\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{3}}}+{\frac{1}{512\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{2}}}+{\frac{1}{128\,da \left ( \sin \left ( dx+c \right ) -1 \right ) }}+{\frac{7\,\ln \left ( \sin \left ( dx+c \right ) -1 \right ) }{512\,da}}-{\frac{1}{160\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{5}}}-{\frac{1}{256\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{4}}}+{\frac{1}{384\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{3}}}+{\frac{5}{512\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{2}}}+{\frac{5}{256\,da \left ( 1+\sin \left ( dx+c \right ) \right ) }}-{\frac{7\,\ln \left ( 1+\sin \left ( dx+c \right ) \right ) }{512\,da}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.03582, size = 289, normalized size = 1.68 \begin{align*} \frac{\frac{2 \,{\left (105 \, \sin \left (d x + c\right )^{8} + 105 \, \sin \left (d x + c\right )^{7} - 385 \, \sin \left (d x + c\right )^{6} - 385 \, \sin \left (d x + c\right )^{5} + 511 \, \sin \left (d x + c\right )^{4} + 511 \, \sin \left (d x + c\right )^{3} - 279 \, \sin \left (d x + c\right )^{2} + 201 \, \sin \left (d x + c\right ) + 96\right )}}{a \sin \left (d x + c\right )^{9} + a \sin \left (d x + c\right )^{8} - 4 \, a \sin \left (d x + c\right )^{7} - 4 \, a \sin \left (d x + c\right )^{6} + 6 \, a \sin \left (d x + c\right )^{5} + 6 \, a \sin \left (d x + c\right )^{4} - 4 \, a \sin \left (d x + c\right )^{3} - 4 \, a \sin \left (d x + c\right )^{2} + a \sin \left (d x + c\right ) + a} - \frac{105 \, \log \left (\sin \left (d x + c\right ) + 1\right )}{a} + \frac{105 \, \log \left (\sin \left (d x + c\right ) - 1\right )}{a}}{7680 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.13217, size = 518, normalized size = 3.01 \begin{align*} \frac{210 \, \cos \left (d x + c\right )^{8} - 70 \, \cos \left (d x + c\right )^{6} - 28 \, \cos \left (d x + c\right )^{4} - 16 \, \cos \left (d x + c\right )^{2} - 105 \,{\left (\cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) + \cos \left (d x + c\right )^{8}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) + 105 \,{\left (\cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) + \cos \left (d x + c\right )^{8}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \,{\left (105 \, \cos \left (d x + c\right )^{6} + 70 \, \cos \left (d x + c\right )^{4} + 56 \, \cos \left (d x + c\right )^{2} - 432\right )} \sin \left (d x + c\right ) + 96}{7680 \,{\left (a d \cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) + a d \cos \left (d x + c\right )^{8}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.26182, size = 211, normalized size = 1.23 \begin{align*} -\frac{\frac{420 \, \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a} - \frac{420 \, \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{a} + \frac{5 \,{\left (175 \, \sin \left (d x + c\right )^{4} - 748 \, \sin \left (d x + c\right )^{3} + 1182 \, \sin \left (d x + c\right )^{2} - 788 \, \sin \left (d x + c\right ) + 155\right )}}{a{\left (\sin \left (d x + c\right ) - 1\right )}^{4}} - \frac{959 \, \sin \left (d x + c\right )^{5} + 5395 \, \sin \left (d x + c\right )^{4} + 12290 \, \sin \left (d x + c\right )^{3} + 14170 \, \sin \left (d x + c\right )^{2} + 8135 \, \sin \left (d x + c\right ) + 1627}{a{\left (\sin \left (d x + c\right ) + 1\right )}^{5}}}{30720 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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